Clojurians Log v2

Hi, how do I find records where opposite values of an attribute are a match. I want to find records where quantity 200 and -200 will match. it is right now giving me empty list as result

data [{:db/id -1
               :date "2024/03/01"
               :payee "Swiggy"
               :quantity 200}
              {:db/id -3
               :date "2024/03/02"
               :payee "Test"
               :quantity 300}
              {:db/id -4
               :date "2024/03/02"
               :payee "Test"
               :quantity 300}
              {:db/id -2
               :date "2024/03/01"
               :quantity -200
               :payee "Swiggy"}]
        f #(db/q '[:find
                   (pull ?t [*]) (pull ?t2 [*])
                   :in $
                   :where
                   [?t :quantity ?q]
                   [?t2 :quantity ?q2]
                   ;; [(= (clojure.core/abs ?q) (clojure.core/abs ?q2))]
                   [(= ?q (clojure.core/* -1 ?q2))]
                   [(not= ?t ?t2)]]
                 %)