Clojurians Log v2
Clojure programming
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core-async
RAJKUMAR 2025-03-10T22:00:27.363049Z
what is wrong with my async code
RAJKUMAR 2025-03-10T22:00:33.766469Z
(let [ch (async/chan)
result (do
(println "inside do")
(async/timeout 50)
(async/>!! ch "bar")
ch)]
(println (async/RAJKUMAR 2025-03-10T22:00:56.947289Z
it only prints "inside do" but not bar
RAJKUMAR 2025-03-10T22:01:16.804689Z
If I increase the channel size to 2 then it prints "bar"
phronmophobic 2025-03-10T22:04:17.043039Z
Writing to ch will block until someone reads from the channel since it's unbuffered. Adding a buffer of 2 means that it can hold two values before blocking.
phronmophobic 2025-03-10T22:04:50.252509Z
also calling (async/timeout 50) won't do anything. You probably meant (async/<!! (async/timeout 50)).
phronmophobic 2025-03-10T22:05:10.650339Z
async/timeout returns a channel.
phronmophobic 2025-03-10T22:05:45.237989Z
(async/chan) returns an unbuffered channel. Try (async/chan 1) to see the difference.
RAJKUMAR 2025-03-10T22:06:12.289879Z
Thanks @smith.adriane
2025-03-10T23:41:20.139609Z
Your code doesn't start any new threads, so you have a thread attempting to write to a channel with no one waiting to read from the channel, so your thread just blocks
2025-03-11T16:27:23.875159Z
You should think of this like a tag team wrestling match. When you read/write to a channel, you're tagging out and tagging in another process.