moin moin

månmån

morning

morning

morning~

mornings!

Morning

lo

Curiosity got the better of me. Seeing some discussion which mentioned the FIZZBUZZ example so wrote it out quickly using map and was curious how others here might tackle the solution differently?

(map
  #(cond
    (= 0 (mod % 3) (mod % 5)) "FIZZBUZZ"
    (= 0 (mod % 3)) "FIZZ"
    (= 0 (mod % 5)) "BUZZ"
    :else %)
  (range 1 101))

Think that's how I'd do it too 🙂

i would use condp but yeah same thing

I might use zero? - but it’s pretty readable

it's a little unfortunate that condp only works for binary predicates

It slightly irks me that you might have to calculate (mod % [3|5]) more than once…

'Ello everyone 🙂

Another FP meetup in Horsham for anyone that might be able to make it (looking at you @mccraigmccraig😉) https://www.meetup.com/Horsham-Functional-Programming/events/248732589/

added to my diary @yogidevbear... not sure if i can yet - my calendar is subject to concurrent modifications and rollbacks